Heat and Reaction Lab
Abstract:
We conducted this experiment to find and calculate the enthalpy using heat. One of the problems being addressed was finding out the mass of the styrofoam calorimeter and the magnesium ribbon. The biggest thing we had to find was the temperature of the HCl when the Magnesium was inside of it. The result was that the temperature kept rising until the time hit 2:15-3:00. Overall, we found the missing temperatures and the mass of the colorimeter and the magnesium ribbon.
Safety Considerations:
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Roll up your sleeves so you won't get any chemicals from the lab on your clothes
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Tie your hair back so the chemicals won't get in your hair
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Wear safety glasses so you won't get anything in your eyes
Materials:
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Styrofoam Colorimeter
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1.0M HCl (Needed 50mL HCL)
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Magnesium Ribbon
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Thermometer
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Spark Temperature Prob
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Test Tube
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Graduated Cylinder
Procedure:
Collect all equipment and put on your safety glasses. Measure out 50.0mL of 1.0M HCl and pour into a pre-weighed calorimeter. Record the mass of the calorimeter + HCl. Record the starting temperature of the HCl. Measure out no more than 0.2g of magnesium ribbon. Record the actual mass. Roll up the Mg ribbon into a loose ball. When ready, place the Mg into the HCl. Quickly place BOTH lids on the calorimeter and slide the thermometer probe into the reaction mixture. Record the temperature every 15 seconds, until the reaction is complete (you'll be able to hear the gas being given off when it's reacting). When the reaction is complete, record the final temperature. Rinse off the thermometer probe and pour the reaction mixture into the waste container, with an equal volume of tap water to neutralize any remaining acid. Clean off your lab table and return to our seats and do this lab write up.
Evidence Collected:
Colorimeter - 26.90
Colorimeter w/ HCl - 76.45
15sec - 26.8
30sec - 29.8
45 sec - 31.1
1 min - 32.5
1:15 - 37.4
1:30 - 39.3
1:45 - 40.8
2 min - 41.5
2:15 - 3 min - 41.8
1.) 2HCl + Mg --> MgCl + H2
2.) Q= m x T x c
= 41.55 x 15 x 4.2
= 3121.65
3.) 3121.65J x 1kJ/1000J = 3.12165kJ
4.) 2g x 1 mol/29.050 = .0082276
5.) kJ/mol = 3.12165kJ/.0082276 = 37935kJ/mol
6.) H = (-801.15) + 0 - 8(-167.2) + 0
= -466.75kJ
7.) Observed - Actual/Actual x 100 = 379.35 - 466.75/466.75 x 100 = -18.72522